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Hoochie [10]
3 years ago
11

Which computer network component allows data transfers from one computer to another through a telephone line?

Computers and Technology
2 answers:
coldgirl [10]3 years ago
7 0
A Router transfer data packets from one node to another node in a network.
Genrish500 [490]3 years ago
5 0

*****ON PLATO*****

Dennis answered that it was a modem. Is the correct answer.

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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Compared with a star topology, a hierarchical topology: a. is more effective at handling heavy but short bursts of traffic. b. a
Eduardwww [97]

Answer:

c. offers a great deal of network control and lower cost.

Explanation:

A network topology can be defined as a graphical representation of the various networking devices used to create and manage a network.

Compared with a star topology, a hierarchical topology offers a great deal of network control and lower cost.

4 0
3 years ago
The unthinkable happens and disaster strikes, crippling your network. You implement your disaster plan, but it doesn't go smooth
Degger [83]

Answer:

Post-mortem.

Explanation:

It refer to the discussion or analysis of event like here disaster why it doesn't work like plan based and through whole discussions what we learn so in future avoid such type of issue or mistakes.

7 0
3 years ago
The HTML tag for the smallest heading is​ what​
Gre4nikov [31]

Answer:

The HTML <h1> to <h6> tag is used to define headings in an HTML document. <h1> defines largest heading and <h6> defines smallest heading.

Explanation:

5 0
3 years ago
Write a pseudocode method swap(aList, i, j) that interchanges the items currently in positions i and j of a list. Define the met
serious [3.7K]

Answer:

Explanation:

The following pseudocode for this method using operations of the ADT list would be the following

swap(aList, indexI, indexJ) {

    initialize temp_variable = Retrieve(indexI, aList)

    Insert(Retrieve(indexJ, aList), indexI, aList)

    Insert(Retrieve(indexI, aList), temp_variable, aList)

}

This code basically saves the aList index of i , into a temporary Variable. Then it sets the aList index of i to the value of the element in index of j. Then it does the same for the index of j with the tem_variable. If we assume that the indexes of i and j exist, then it can crash our entire program if those indexes are missing from the list when we try to access them.

6 0
3 years ago
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