Answer:
- h = 0 when the ball hits the ground
- about 3.464 seconds
Step-by-step explanation:
The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.
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Using that in the equation, we can solve for t.
0 = 192 -16t^2
0 = 12 -t^2 . . . . . . divide by 16
t^2 = 12 . . . . . . . . add t^2
t = √12 = 2√3 ≈ 3.464 . . . . take the square root
It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.
Answer:
6 containers needed
Step-by-step explanation:
Given
----- Size
----- Size
Required
Determine the number of containers needed
This question illustrates the knowledge of fraction and division.
To get the number of containers needed, we simply divide the total size by the size of the container as follows;
Convert to improper fractions
--- Approximated
For the first one,
you multiply 5x and -5 to get -25.
Then you move the constant to the right and change the sign to get 3x= -21 +25.
Calculate the sum of -21+25 to get 4.
Divide both sides of the equation by 3 to get x=4/3.
So then your final answer is x=4
——
3
For the second one,
Distribute 7 through the parentheses to get 14x + 14+8=120
The you add 14+8 to get 22. Your equation should be 14x+22=120
Move the constant to the right side and change its sign to get 14x=120-22
Subtract 120-22 to get 98. Now your equation should be 14x=98
Divide both sides of the equation by 14 to get x=7.
Your finial answer for the second one should be x=7.
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I hope this made sense.
So the problems ask to find and calculate the exact value of the trigonometric equation in the following equations and the best answers would be the following:
#1. sqrt(3)/3
#2. Arcsine of zero is 0
#3. x/sqrt(4-x^2)
I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications. Have a nice day
Answer:
C. 19
B. 47
C. 12
C. 10
C. -8
Step-by-step explanation:
for each equation you take the number given, input it as the value of the variable, and evaluate the equation
hopefully this helps :)
