Answer:
9 and 10
Step-by-step explanation:
To start, let's have what we know:
a and b are two consecutive positive integers
a = first integer
b = second integer, 1 greater than variable a
b = a + 1
b^2 = 19 + 9a
To solve this, we would only have to substitute values in
b^2 = 19 + 9a
(a+1)^2 = 19 + 9a
a^2 + 2a +1 = 19 + 9a
-9a -19 -19 - 9a
a^2 -7a - 18 = 0
a^2 + 2a - 9a - 18
a(a + 2) - 9(a+2) = 0
(a - 9)(a + 2) = 0
So solving this, we would get a = 9 or a = -2. Since this is supposed to be a positive integer, a will be 9.
Solving for b,
b = a + 1
= 9 + 1
= 10
Let me know in the comments if you have any questions! If you could mark this answer as brainliest, I would very much appreciate it!
Answer:
(x-4) (x-2)
Step-by-step explanation:
x^2−6x+8
What 2 numbers multiply to 8 and add to -6
-4*-2 = -8
-4+-2 = -6
(x-4) (x-2)
Answer:
Step-by-step explanation:
a) <u>Number of girls:</u>
<u>Percentage:</u>
b) <u>Number of students prefer watching TV:</u>
<u>Percentage:</u>
DE + EF = 4x+2
DE = x+7
EF = 7
Substitute these in
x + 7 + 7 = 4x + 2
x + 14 = 4x + 2
subtract x from both sides
14 = 3x + 2
subtract 2 from both sides
3x = 12
divide both sides by 3
x = 4
substitute this in to find the length of DE
DE = x + 7
(4) + 7 = 11
the answer is 11