For a line that goes through points (2,-2) and (1.-6), what is the equation

Mathematics

1 answer:

Inessa [10]2 years ago

3 0

Answer:

Step-by-step explanation:

$\text{The point-slope form of an equation of a line:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\(x_1,\ y_1)-point\ on\ a\ line\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\======================================$

$\text{We have the points:}\ (2,\ -2)\ \text{and}\ (1,\ -6).\\\\\text{Substitute:}\\\\m=\dfrac{-6-(-2)}{1-2}=\dfrac{-4}{-1}=4\\\\y-(-2)=4(x-2)\\\\y+2=4(x-2)$

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$Day \ \ \ \ \ \ \ \ \ \ Period \ \ \ \ \ \ \ \ \ \ Demand \ \ \ \ \ \ \ \ \ \ 5-period moving average$

$1 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 37 \\\\$

$Afternoon \ \ \ \ \ \ \ \ \ \ \ 25 \\\\ Evening \ \ \ \ \ \ \ \ \ \ \ 9$

$2 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \48 \\\\$

$Afternoon\ \ \ \ \ \ \ \ \ \ \ 28 \\\\$

$Evening \ \ \ \ \ \ \ \ \ \ \ 14 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.4 \\\\$

$3 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 53 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24.8\\\\$

$Afternoon \ \ \ \ \ \ \ \ \ \ \ 33 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30.4\\\\Evening \ \ \ \ \ \ \ \ \ \ \ 17 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35.2\\\\$

$4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29\\\\$

$Afternoon\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.25\\\\Evening \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34.33333\\\\$