A tree casts a shadow of 28 feet. At the same time, a biologist who is 7 feet tall casts a shadow of 2 feet.

1 answer:

4 0

Assuming that this happened at the same environment like the time of day, then we can use ratio and proportion. We relate the height of the tree with its shadow by using the ratio of the biologist's height to his shadow.

Height of tree/Height of its Shadow = Height of biologist/Height of his Shadow
Height of tree/28 = 7/2
Height of tree = 7*28/2
Height of tree = 98 feet

The answer is D.

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Need help with this easy math problem

steposvetlana [31]

Answer:

B=43 C=137 D=48

Step-by-step explanation:

b=43 because any small triangle you subtract each angle from 180 . 180-89-48= 43

c=137 because angle b and c make a supplementary angle so you subtract b from 180 to get c. 180-43= 137

d=48 because <edc is congruent to <eyx so they are the same size

4 0

3 years ago

MATH PROBLEM!! CAN SOMEONE HELP 25pts You roll two number cubes at the same time. Let X be a random variable that represents the

Vesna [10]

Answers:

(a) Possible values of X are: 0, 1, 2, 3, 4, 5

(b) See attached image below; specifically figure 2

(c) No, it is <u>not</u> symmetric

(d) As a fraction, the answer is 1/6. In decimal form, the answer is approximately 0.1667 (converts to roughly 16.67%)

=========================================

Explanations:

(a) The largest possible roll we can get on one die is 6, the smallest is 1, so the largest possible difference is 6-1 = 5. The smallest difference is 0 as we could get doubles (eg: both dice show a "3" at the same time). We can get any difference in between 0 and 5. So X can take on whole numbers from 0 to 5, ie, X can be any number from the set {0, 1, 2, 3, 4, 5}

(b) Consult the attached image. Figure 1 shows a 6 by 6 grid of values that represent all the possible ways to roll two dice. Each value in the interior of the grid is the result of subtracting the outer header values. Figure 2 is where the answer is shown for part b. The idea is that you list out the X values along the top of the table and the probability P(X) values along the bottom row. I show the work on how to compute each probability in the attachment. The probability is equal to the number of occurences over the number total. Example: X = 3 shows up 6 times out of 36, so P(X) is 6/36 = 1/6 when X = 3.

(c) The distribution is not symmetric as figure 3 shows a lop-sided diagram. The mode should be at the center, but this figure shows the mode off to the left side.

(d) Count how many copies of '4' or '5' show up in the interior of the grid shown in figure 1. There are four copies of '4' and two copies of '5'. Overall there are 4+2 = 6 instances of either '4' or '5'. This is out of 36 total, so 6/36 = 1/6 is the fractional form of the answer which approximates to 0.1667 and converts to 16.67% approximately.