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2 years ago

If Jenny walks 2 miles in 40 minutes, then Jenny will walk how far in 100

Mathematics

1 answer:

Snezhnost [94]2 years ago

3 0

Answer:

Five miles

Step-by-step explanation:

if 2=40 then 1=20 so 5=100

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By what percent would the area of the rectangle change if the width of the rectangle is increased by 50% and the length is incre

belka [17]

Answer:

. i think it's wrong

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3 years ago

Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)

strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

if $a>0$ -------> the parabola open upward (vertex is a minimum)

if $a$ -------> the parabola open downward (vertex is a maximun)

case A) $f(x)=(x-2)^{2}$

This is a vertical parabola open upward

the vertex is the point $(2,0)$

therefore

The function $f(x)=(x-2)^{2}$ does not have a vertex on the y-axis

case B) $f(x)=x(x+2)$

$f(x)=x(x+2)=x^{2}+2x$

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+1=x^{2}+2x+1$

Rewrite as perfect squares

$f(x)+1=(x+1)^{2}$

$f(x)=(x+1)^{2}-1$

the vertex is the point $(-1,-1)$

therefore

The function $f(x)=x(x+2)$ does not have a vertex on the y-axis

case C) $f(x)=(x-2)(x+2)$

$f(x)=(x-2)(x+2)=x^{2}-2^{2}$

$f(x)=x^{2}-4$

the vertex is the point $(0,-4)$

The x-coordinate of the vertex is equal to zero

therefore

The function $f(x)=(x-2)(x+2)$ has a vertex on the y-axis

case D) $f(x)=(x+1)(x-2)$

$f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2$

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+2= x^{2} -x$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+2+0.25= x^{2} -x+0.25$

$f(x)+2.25= x^{2} -x+0.25$

Rewrite as perfect squares

$f(x)+2.25= (x-0.50)^{2}$

$f(x)=(x-0.50)^{2}-2.25$

the vertex is the point $(0.5,-2.25)$

therefore

The function $f(x)=(x+1)(x-2)$ does not have a vertex on the y-axis

the answer is

$f(x)=(x-2)(x+2)$

6 0

3 years ago

Read 2 more answers

State the various transformations applied to the base function to obtain a graph of the functiong(x) = |x + 1| − 2.

Arlecino [84]

345 i love your mom and I love your hair

7 0

3 years ago

Which of these is the best definition of an ellipse?

MArishka [77]

Answer:

I think it's B.

Step-by-step explanation:

Sorry if I'm wrong :/

4 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP ME!!! I REALLY NEED SOME HELP!!!

Lostsunrise [7]

Answer:

A. (1, -2)

Step-by-step explanation:

We can substitute the variables of x and y into the inequality of $y < -|x|$ .

Let's start with A, -2 being y and 1 being x.

$-2 < - |1|$

The absolute value of 1 is 1, and negating that gets us -1.

$-2 < -1$

Indeed, -2 is less than -1! So A is a solution to the inequality.

Let's test the rest of them, just in case.

For B:

$-1 < -|1|$

Absolute value of 1 is 1, negating it is -1.

$-1$

-1 is EQUAL to -1, not less than it, so is not a solution to the inequality.

Let's try C.

$0 < -|1|$

Absolute value of 1 is 1, negating it is -1.

$0 < -1$

0 is GREATER than -1, so that is not a solution to the inequality.

Hope this helped!

4 0

3 years ago