<h3>
Answer: Multiply by 4</h3>
This is because 1 quart = 4 cups
So if you had say 3 quarts, then it converts to 3*4 = 12 cups.
Answer:
Um.. well I don't know what is your question, but I think you meant square root and the answer is 7 because it is a perfect square.
Step-by-step explanation:
Let's see what the options look like when we multiply the expressions in brackets:
(first, i multiply both parts of the second bracked by the first part of the first bracket, and then the same with the second part of the first bracket:
<span>(1) (3x - 3)(x - 2))
3x2 +6x -3x +6// this is not correct
(2) (3x + 3)(x - 2) </span>
3x2-6x+3x-6//this is not correct
(3)
3(x + 1)(x - 2)
3(x2-2x+x-2)//simplifying:
3(x2-x-2)//multiplying:
3x2-3x-6)
- so this is not correct either
(4) 3(x - 1)(x - 2)
3(x2-2x - x + 2)
3(x2-3x +2)
3x2-9x +6 - well, here is our winner!
What are your answer choices
Answer:
From top to bottom:

Step-by-step explanation:
We are given the piecewise function:

Row 1:
We want to find g(-2).
Since -2 is less than (or equal to) 2, we will use the first equation. Thus:

Row 2:
Likewise, 0 is less than or equal to 2. We will continue to use the first equation:

Row 3:
2 is not less than 2 but it is equal to 2. So we will continue to use the first equation:

Row 4 and 5:
Both 4 and 6 are greater than 2. Thus, we will use the second equation. Therefore:
