Find Y if AB bisects DAC and CB bisects ACE
1 answer:
Answer:
L1 and L2 are parallel
BAC = 58° as it is given in the question that AB bisects DAC
similarly BCE = y°
angle B = 90° ( from figure)
Y + 58° + 90° = 180 ( angle Sum property of a triangle).
Y + 148° = 180°
Y = 180 - 148
Y = 32°
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