The volume would be 5.5 cubic units.
First, we need to find the volume of one cube. It would be LWH.
0.5 x 0.5 x 0.5 = 0.125
Now, just multiply that volume by 44.
0.125 x 44 = 5.5
Answer:
products : (2abc) × (– 5ab) ×(– 6c)
2abc×-5ab×-6c
-×-×2×5×6×a×a×b×b×c×c
+60×a²×b²×c²
60a²b²c² is your answer. here -×-=+
Answer:
cat is your answer
Step-by-step explanation:
Answer:
5.3×10⁻¹¹ m
Step-by-step explanation:
Applying,
v = 2πr/t................ Equation 1
Where v = speed of the electron in the orbit, r = radius of the orbit, t = time, π = pie
make r the subject of the equation
r = vt/2π................ Equation 2
From the question,
Given: v = 2.2×10⁶ m/s, t = 1.5×10⁻¹⁶ s
Constant: π = 3.14
Susbtitute these values into equation 2
r = (2.2×10⁶×1.5×10⁻¹⁶)/(3.14×2)
r = (3.3×10⁻¹⁰)/6.28
r = 5.3×10⁻¹¹ m
Hence the radius of the orbit is 5.3×10⁻¹¹ m