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REY [17]
3 years ago
13

The table your working at keeps wobbling. You decide to fix it by making a thick pad of paper from folded sheets of paper. Each

time you fold a sheet in two, the number of layers doubles. You fold a first sheet of paper 3 times and stick it beneath the wobbly leg. It doesn’t quite do the trick, so you fold another sheet of paper 2 times and put it beneath the wobbly leg too. In total, how many layers of paper did it take to prop up the table?
Mathematics
1 answer:
loris [4]3 years ago
5 0
To answer this question and you will use exponents.

When you fold your paper three times, it is represented as two cubed or 2^3.

When you for your other sheet of paper two times, it is represented as two squared or 2^2.

Put Both of these together and you have 8+4 which equals 12.

It will take 12 layers of paper.
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lana [24]

Convert 3 1/2 to a improper fraction:

3 1/2 = 7/2

Divide 7/2 by 1/4:

7/2 ÷ 1/4

7/2 × 4/1

28 / 2

= 14

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5 0
4 years ago
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elixir [45]

Answer: 1400

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8 0
3 years ago
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Please help marking brainlist
Arada [10]

Answer:

7/10

Step-by-step explanation:

Try 7/10

(7/10)^2=49/100

3 0
3 years ago
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the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?
olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= \frac{-3y}{y-1}

Similarly fourth term will be

x-3y-2y=x-5y

x-5y=\frac{x}{y}

substitute the value of x  in the equation

\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0

Split the middle term and factorize it

5y^{2}+3y-5y-3=0\\y(5y+3)-1(5y+3)=0\\

(y-1)(5y+3)=0

y=1,\frac{-3}{5}

y cannot be equal to 1, because the third term and fourth term will become x.

y=\frac{-3}{5}

substitute the value of y in the equation of x
x=\frac{-3y}{y-1} \\=\frac{-3\frac{-3}{5} }{\frac{-3}{5}-1 }\\ =\frac{-9}{8}

The fifth term= \frac{x}{y}+(-2y)=\frac{x}{y} -2y

\frac{\frac{-9}{8} }{\frac{-3}{5} }-2\frac{-3}{5}  =\frac{123}{40}

Hence, when the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

Learn more about Arithmetic sequence here

brainly.com/question/15412619

#SPJ4

5 0
2 years ago
Misaki’s fish tank is half full of water because she is cleaning it. The tank is a right rectangular prism with a length of 8 in
Sophie [7]
Answer is 288 inches cubed
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3 years ago
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