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lesya [120]
1 year ago
5

What is the smallest positive integer $n$ for which $n^2$ is divisible by 18 and $n^3$ is divisible by 640

Mathematics
1 answer:
liberstina [14]1 year ago
8 0

The smallest positive integer n for which n^2 is divisible by 18 and n^3 is divisible by 640 is 120

The modulo (or "modulus" or "mod") is the remainder after dividing one number by another.

The smallest integer is 120, since:

120^{2} mod 18 = 0, (reminder after dividing 120^{2} by 18 is 0) and

120^{3} mod 640 = 0 (reminder after dividing 120^{3} by 18 is 0)

Hence, The smallest positive integer n for which n^2 is divisible by 18 and n^3 is divisible by 640 is 120.

Learn more about Divisibility here

brainly.com/question/8226236

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