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Margarita [4]
1 year ago
8

Hi I need help with the question in the image. Step by step, thank you!

Mathematics
1 answer:
VashaNatasha [74]1 year ago
6 0

The exponential function is f(x) = 18(12)^{-x-4} + 2

<h3>How to determine the equation?</h3>

An exponential function is represented as:

y = b^x

Where b represents the base.

The base is given as:

b = 12

So, we have:

y = (12)^x

It is vertically compressed by a factor of 1/8.

So, we have:

y = 18(12)^x

When reflected across the y-axis, we have:

y = 18(12)^{-x}

The horizontal asymptote is y = 2.

So, we have:

y = 18(12)^{-x} + 2

It passes through the point (-3, 4).

So, we shift the function to the right by 4 units

y = 18(12)^{-x-4} + 2

Express as a function

f(x) = 18(12)^{-x-4} + 2

Hence, the exponential function is f(x) = 18(12)^{-x-4} + 2

Read more about exponential functions at:

brainly.com/question/14355665

#SPJ1

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An acute angle, θ, is in a right triangle such that sin of theta is equal to 3 over 8 period What is the value of cot θ?
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We want to find the value of cot(θ) given that sin(θ) = 3/8 and θ is an angle in a right triangle, we will get:

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So we know that θ is an acute angle in a right triangle, and we get:

sin(θ) = 3/8

Remember that:

  • sin(θ) = (opposite cathetus)/(hypotenuse)
  • hypotenuse = √(  (opposite cathetus)^2 +  (adjacent cathetus)^2)

Then we have:

opposite cathetus = 3

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