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3 years ago

Need some help on this one

Mathematics

2 answers:

disa [49]3 years ago

5 0

The answer is most people who own cats would most like dislike dogs.
B.

Ivan3 years ago

5 0

B. Most people who own a cat do not like dogs

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What is the axis of symmetry of g(x)=2(x-4)(x+2)

maksim [4K]

I think the answe would be 4(56x)

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3 years ago

heyyy! i haven't posted a question in a long time lolz. anyways, i really needed help with this!! if you can answer my question

Andre45 [30]

2 ones and 8 hundredths

00.00
the first zero is tens, ones, and after the decimal, to the right is the tenths, hundredths and so on

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3 years ago

Rachel types 162 words in 3 minutes. Rachel types at a constant rate.

Mazyrski [523]

Answer:

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Step-by-step explanation:

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3 years ago

Can anyone help me with this, I’ll give out brainliest. NO LINKS.

Sliva [168]

Answer:

89.132 inch

Step-by-step explanation:

“this shape is made up of one half-circle attached to a square with side lengths 16 inches. You can use 3.14 as an approximation.”

so, the square has a perimeter of 16 inch, four sides that will be 64 inch

then the half circle rule of perimeter of half circle: πr + 2r

=> perimeter of semicircle = π * 8 +2 * 8 = 41.132 inch

without the bottom line of half circle= 41.132 -16 = 25.133 inch

So total 25.133 + 64 =89.132 inch

have a great day and nc question

4 0

2 years ago

On Sundays, cars arrive at Sami Schmitt's Scrub and Shine Car Wash at the rate of 8 cars per twenty minute interval. Using the P

Sliva [168]

Answer:

The probability that five cars will arrive during the next thirty minute interval is 0.0127.

Step-by-step explanation:

Let X = number of cars arriving at Sami Schmitt's Scrub and Shine Car Wash.

The average number of cars arriving in 20 minutes is, 8.

The average number of cars arriving in 1 minute is, $\frac{8}{20}=\frac{2}{5}$ .

The average number of cars arriving in 30 minutes is, $\frac{2}{5}\times 30=12$ .

The random variable X follows a Poisson distribution with parameter λ = 12.

The probability mass function of X is:

$P(X=x)=\frac{e^{-12}12^{x}}{x!};\ x=0,1,2,3...$

Compute the probability that 5 cars will arrive in 30 minutes as follows:

$P(X=5)=\frac{e^{-12}12^{5}}{5!}$

$=\frac{6.1442\times10^{-6}\times 48832}{120}$

$=0.0127$

Thus, the probability that five cars will arrive during the next thirty minute interval is 0.0127.

6 0

3 years ago