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3 years ago

Need some help on this one

Mathematics

2 answers:

disa [49]3 years ago

5 0

The answer is most people who own cats would most like dislike dogs.
B.

Ivan3 years ago

5 0

B. Most people who own a cat do not like dogs

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The average number of customers per day increased 25 percent during the sale. If the average number of customers per day before

Rasek [7]

Answer:

The average number of customers per day during the sale was 150.

Step-by-step explanation:

This question can be solved using a rule of three.

Before the sale, the average number of customers per day was 120, which is 100% = 1.

Now, there are x customers, and since it is an increase of 25%, it is 100+25 = 125% = 1.25. So

120 - 1

x - 1.25

x = 1.25*120 = 150

The average number of customers per day during the sale was 150.

6 0

4 years ago

Find the length of the third side to the nearest tenth.<br> 3 7

kogti [31]

Answer:

uhm 5?

Step-by-step explanation:

because 3 we move 1 more is 4.

and 7 we go -1 which is 6 so we have 5 in the middle so the answer is 5!

5 0

3 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

The midpoint of AB is M(0, 3) If the coordinates of A are (4, - 1) , what are the coordinates of B?

Harlamova29_29 [7]

-4;4

XB=0*2-4

YB=3*2-(-1)

3 0

3 years ago

Math help please i have discalcula

user100 [1]

Answer:

x=4y,3x=4y,y=4x,4x=3y

5 0

3 years ago