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3 years ago

How do you factor 2y^2 +13 +21

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

2(y^2+17)

Step-by-step explanation:

First, add 13 and 21 together.

You'll end up with 2y^2+34

Then, factor out the two from each term, to get 2(y^2+17).

Since you can factor nothing else out, that will be your answer.

ella [17]3 years ago

3 0

Answer:

(

)

Step-by-step explanation:

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Picture here you go! Thanks

vazorg [7]

Answer:

8/3x + 6 (first option)

Step-by-step explanation:

Well youc an use the destructive property, multiply 2/3 with each number in this expression

2/3* 4x= 8/3x

and

2/3 *9 is 6

Now just plug it in as usual

8/3x+6

6 0

2 years ago

Read 2 more answers

Which sequence represents an arithmetic sequence?

MArishka [77]

Answer:

Step-by-step explanation:

We know that an arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is always constant.

−5, −7, −10, −14, −19, …

Here difference between -5 and -7 is -2

But difference between -10 and -7 is -3

⇒ Difference is not constant.

Therefore, this sequence does not represents an arithmetic sequence.

1.5, −1.5, 1.5, −1.5, …

Here difference between 1.5 and -1.5 is 3

But difference between -1.5 and 1.5 is 3

⇒ Difference is not constant.

Therefore, this sequence does not represents an arithmetic sequence.

4.1, 5.1, 6.2, 7.2, …

Here difference between 4.1 and 5.1 is 1

But difference between 6.2 and 5.1 is 1.1

⇒ Difference is not constant.

Therefore, this sequence does not represents an arithmetic sequence.

−1.5, −1, −0.5, 0, …

Here difference between -1.5 and -1 is 0.5

But difference between -1 and -0.5 is 0.5

⇒ Difference is constant.

Therefore, this sequence represents an arithmetic sequence.

plz mark brainliest

7 0

3 years ago

Which ordered pair makes both inequalities true y x 1 YX?

denis-greek [22]

The ordered pair which makes both inequalities true is (-2, 2).

It is given that inequalities are

y < -x + 1 and y > x

For y < -x + 1

Substituting every ordered pair,

1) (-3, 5)

⇒ 5 < - (-3) + 1

⇒ 5 < 3 + 1

⇒ 5 < 4 is false

2) (-2, 2)

⇒ 2 < -(-2) + 1

⇒ 2 < 2 + 1

⇒ 2 < 3 is true

3) (-1, -3)

⇒ -3 < - (-1) + 1

⇒ -3 < 1 + 1

⇒ -3 < 2 is true

4) (0, -1)

⇒ -1 < -0 + 1

⇒ -1 < 1 is true

Now , for y > x

1) (-3, 5)

⇒ 5 > -3 is true

2) (-2, 2)

⇒ 2 > -2 is true

3) (-1, -3)

⇒ -3 > -1 is false

4) (0, -1)

⇒ -1 > 0 is false

Therefore ,the ordered pair which makes both inequalities true is (-2, 2).

To know more about Inequalities here

brainly.com/question/11612965

#SPJ4

5 0

1 year ago

Which quadratic equation equation is equivalent to (x^2-1)^2 -11(^2-1) +24=0

cluponka [151]

$(x^2-1)^2-11(x^2-1)+24=0$

Use substitution: $x^2-1=t$

$t^2-11t+24=0\\\\t^2-8t-3t+24=0\\\\t(t-8)-3(t-8)=0\\\\(t-8)(t-3)=0\iff t-8=0\ \vee\ t-3=0\\\\t=8\ \vee\ t=3$

<span>we're going back to substitution:

$x^2-1=8\ \vee\ x^2-1=3\ \ \ \ |add\ 1\ to\ both\ sides\ of\ the\ equations\\\\x^2=9\ \vee\ x^2=4$

therefore

$x=\pm\sqrt9\ \vee\ x=\pm\sqrt4\\\\\boxed{x=-3\ \vee\ x=3\ \vee\ x=-2\ \vee\ x=2}$
</span>

6 0

3 years ago

Read 2 more answers

The expression 4x, x gives the perimeter of a square with a side length of xxx units.

MA_775_DIABLO [31]

Answer: 20 over 7 units

Step-by-step explanation:

5 0

3 years ago