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nirvana33 [79]
1 year ago
9

Which ordered pair makes both inequalities true y x 1 YX?

Mathematics
1 answer:
denis-greek [22]1 year ago
5 0

The ordered pair which makes both inequalities true is (-2, 2).

It is given that inequalities are

y < -x + 1 and y > x

For  y < -x + 1

Substituting every ordered pair,

1) (-3, 5)

⇒ 5 < - (-3) + 1

⇒ 5 < 3 + 1

⇒ 5 < 4 is false

2) (-2, 2)

⇒ 2 < -(-2) + 1

⇒ 2 < 2 + 1

⇒ 2 < 3 is true

3) (-1, -3)

⇒ -3 < - (-1) + 1

⇒ -3 < 1 + 1

⇒ -3 < 2 is true

4) (0, -1)

⇒ -1 < -0 + 1

⇒ -1 < 1 is true

Now , for  y > x

1) (-3, 5)

⇒ 5 > -3 is true

2) (-2, 2)

⇒ 2 > -2 is true

3) (-1, -3)

⇒ -3 > -1 is false

4) (0, -1)

⇒ -1 > 0 is false

Therefore ,the ordered pair which makes both inequalities true is (-2, 2).

To know more about Inequalities here

brainly.com/question/11612965

#SPJ4

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Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

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D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
Can someone write the equation that goes with this table? (thanks!!)​
Andreas93 [3]

Answer:

It can be observed that the value of y is the value of x multiplied by -2. Hence the equation would be y=-2x.

4 0
3 years ago
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