m3 = 110°
Step-by-step explanation:
m1 = 180° - m4 ( sum of angles in a straight angle )
m1 = 180° - 150° = 30°
m3 = 180° - (m2 + m1) ← sum of angles in a triangle
m3 = 180° - (40 + 30 )° = 180° - 70° = 110°
Answer:
dimension are 350 m and 350 m and
area is 122500 m²
Step-by-step explanation:
Given data
perimeter is 700 m
to find out
the largest area and its dimensions
solution
we consider x and y are the sides
so area is xy
perimeter is 2x+ y = 700
so we can say y = 700 -2x
so area will be = x (700 - 2x)
area = 700x - 2x²
we take derivative here and equal to zero
dA/dt = 700x - 2x²
700 - 4x = 0
x = 700/4
x = 175
so will be
y = 700 -2x
y = 700 -2(175)
y = 350
so dimension are 350 m and 350m
area is 122500 m²
The answer usually question what does this question do you think Association
T=d/v
540/(230+w)=380/(230-w)
540(230-w)=380(230+w)
124200-540w=87400+380w
124200-920w=87400
-920w=-36800
w=40
So the wind speed is 40 miles per hour.
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.
A=B
Method 1:
We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5
B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º ⇒ C=2*40º=80º
Answer:
a=7; A=50º
b=7; B=50º
<span>c=9; C=80º
Method 2:
Law of cosines:
a²=b²+c²-2bcCosA ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º
B=A=50º
A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º
Answer:
</span>a=7; A=50º
b=7; B=50º
<span>c=9; C=80º</span>