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500×((1+0.06÷12)^(12×25)−1)÷(0.06÷12)
=346,496.98
4x^2-9
(2x+3)(2x-3)
To verify use distributed
2x(2x) +2x(-3)+3(2x)+3(-3)
4x^2-6x+6x-9
4x^2+0-9
4x^2-9
R=S*0.5^(t/8)
<span>R is the remaining amount </span>
<span>S is the starting amount (500) </span>
<span>0.5^ is for the HALF in half-life </span>
<span>t/8 show that every 8 ts (every 8 hours), it will be halved once </span>
<span>...so plug in 500mg for the general solution... </span>
<span>R=(500)*(0.5)^(t/8) </span>
<span>... plug in 24h to solve for after 24h </span>
<span>R=(500)*(0.5)^(24/8) </span>
<span>R=(500)*(0.5)^(3) </span>
<span>R=(500)*(0.125) </span>
<span>R=(0.0625) </span>
<span>...therefore there with be 0.0625 mg of the dose remaining</span>
