The hypotenuse is 20.59. 10^2+18^2=C^2
the anwser is
Step-by-step explanation:
the anwser is 5 kg
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
I think the equation is 7l +5=60
Step-by-step explanation:
7 + 14x means that a number x (x could be any real number) times 14 is added to 7.
So if x = 2:
7 + 14x = 7 + 14(2) = 28 + 7 = 35
Happy to help!
