The answer just keeps coming back to zero dude it's simple you can't really calculate this either way the value of it would just be zero you can't simplify it or anything
Answer:
AC = 12.5 cm
Step-by-step explanation:
use cosine law c^2 = a^2 + b^2 − 2ab cos(C)
c^2 = 6^2 + 10^2 - 2(6)(10)(cosin100)
c^2 = 156.84
c= √156.84
c= 12.5 cm
The cosine rule is used when we are given either three sides or two sides and the included angle.
Answer:
P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.
Step-by-step explanation:
P and Q are the intersection points of
x-y+1 = 0 and the circle x^2 + y^2 = 25
sub y = x+1 into the circle
x^2 + (x+1)^2 = 25
x^2 + x^2 + 2x + 1 - 25 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = 3 or x = -4
y = 4 or y = -3
so P(3,4) and Q(-4,3) are our two points
Height of triangle.
h = |0 - 0 + 1|/√2 = 1/√2
PQ = √( (-7)^2 + 1^2) = √50 = 5√2
area POQ = (1/2)(1/√2)(5√2) = 5/2 square units
hope this helped
Answer:
227.5
Step-by-step explanation: You have to multiply 3.5 times 65
Hope this helps!!!
