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krok68 [10]
3 years ago
7

A few years ago, the Colorado Rockies played 160 games and won 64. for every two games they won, how many games did they lose?

Mathematics
2 answers:
Monica [59]3 years ago
7 0

The answer is A 3.

In order to find this answer, we first have to find the number of games that they lost. To do so, we subtract the wins from the total.

160 - 64 = 96.

Now that we have the number of losses, we can divide wins by losses to get a ratio.

64/96 = 2/3

So for every 2 wins, we get 3 losses.

dusya [7]3 years ago
4 0

Answer:

A. 3

Step-by-step explanation:

Given: Colorado Rockies played 160 games and won 64.

To find: For every two games they won, how many games did they lose?

Solution: In order to find for every two games they won, how many games did they lose, we first need to find the number of games they lose.

So, we have

total games=160

games won=64

games lose=160-64=96

Now, we need to find the ratio of number of games won to the number of games they lose

=\frac{64}{96}

=\frac{2}{3}

Therefore, the ratio is 2:3.

So, for every 2 games they won, they lose 3 games.

Hence, option A. 3 is correct.

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ycow [4]

Answer:

a) Mode number = 2

b) Median  = 64.5  = 4 people in car as 0.5 in 64.5 is close to 76

              = 4 people

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Step-by-step explanation:

45  is 1

198 is 2

121 is 3

76 is 4

52 is 5

13 is 6

Mode we look for the highest frequency and see 198 is the amount and 2 people in car is the subject, we give the subject and that is 2 people in car is the highest frequency and would be the mode.

Median is shown in the answer as we add up.

Mean we add up all frequency and divide by the amount of subjects = 6.

a) Mode number = 2

b) Median = 13, 45, 52, here 76, 121, 198    mid number between

             = (76-52 )/ 2  + (52)= 24 /2 + (52) = 12 + 52 + 0.5 if even number    

median  = 64.5  in a cumulative graph though which is not asked here it would be exactly half of 505 = 257.5 and interquartile we half again and add on 257.5 and show the range values interquartile as 1/2(252.5) and 1/2(252.5+ 505) = 126.25 as one value and 757.5 as the other by drawing a horizontal line from y axis to the points so vertical lines can represnt the cars median and interquartile.

c. Mean number is  505/6 =   84.1666666667 then we see where 84.16 lies and see this lies with 3 seats

For cumulative frequency we can relist numbers like this

45

45 +198 = 243

243 +  121 = 364

364+76 = 440

440 + 52 = 492

492+13 = 505 to plot graph.

But if there was group of measures or time etc then we would always plot the highest of each set for cumulative x axis and use the 2 values to see the ratio for histograms ie) 198/2 = 99 so that all values are read in equal proportions and 2 is a data below the graph not on the graph as 2 does not show as a box count just a name below on x axis. So we have to use the ratio as explained for histograms.

8 0
3 years ago
A fair die is rolled 5 times. What is the probability that a 3 is obtained on at least one of the rolls? Round your answer to th
Lerok [7]

Answer:

0.200

Step-by-step explanation:

The probability of obtaining a 3, in one roll of a fair die is 1/6.

Now, we have 5 rolls.

We now want to know the probability of a 3 showing up in at least one of the rolls.

This simply mean, we add the probabilities of three showing one time plus probability of three showing in 2 of the rolls e.t.c

This means we can have 3 showing up to 5 times.

We add the probabilities as follows:

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3 0
3 years ago
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