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Ludmilka [50]
2 years ago
11

Given the data set in the image, which of the following equations best represents a line of best fit?

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
7 0

Answer:

C.

Step-by-step explanation:

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Four less than two-thirds of a number is equal to twice the number. What is the number
Ket [755]

Answer:

n = -3


Step-by-step explanation:

Let the number be n.  Then (2/3)n-4 = 2n.

Solve for n.  To accomplish this, start by mult. both sides by 3, to remove the fractional coefficient:  2n - 12 = 6 n, or -12 = 4n.  then n = -3 (answer)


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3 years ago
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Convert 12 7/12 to a common number
o-na [289]
As a decimal it is 0.58
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3 years ago
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What is an equation for the line that passes through (-2,-3) with a slope of -1/2?
Crazy boy [7]

Answer:

C

Step-by-step explanation:

To write the equation of a line use the point slope form of a line substituting m = -1/2 and the point (-2,-3).

y -y_1 = m(x-x_1)\\y --3=-\frac{1}{2}(x--2)\\y+3 = -\frac{1}{2}(x+2)

Convert to standard form by applying the distributive property and rearranging the terms.

y + 3 = -\frac{1}{2}(x+2)\\y+3 = -\frac{1}{2}x -1\\2y + 6 = -x -2\\x+2y + 6 = -2\\x + 2y = -8

The equation x +2y = -8 is the same equation as 4y + 2x = -16 just doubled----> 2x + 4y = -16

8 0
3 years ago
The Yoga class you wish to take is offering two price quotes: $108 for 5 weeks as (15 classes) or $125 for 8 weeks (24 classes).
AURORKA [14]
The answer is C)
108/15 - 125/24 = 1.99
4 0
3 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil
Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 83, \sigma = 3

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 83}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0
3 years ago
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