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weeeeeb [17]
3 years ago
6

The base of the parallelogram, b, can be found by dividing the area by the height.

Mathematics
2 answers:
MaRussiya [10]3 years ago
7 0
The area of a parallelogram is:
 A = b * h
 Where,
 b: base
 h: height
 Clearing the base we have:
 b = A / h
 Substituting values we have:
 b = (6x2 + x + 3) / 3x
 Rewriting we have:
 b = 2x + 1 / x + 1/3
 Answer:
 the length of the base is:
 b = 2x + 1 / x + 1/3
svet-max [94.6K]3 years ago
5 0

Answer:

b =  2x+\frac{1}{3}+\frac{1}{x}

Step-by-step explanation:

The area of the parallelogram is represented by 6x^{2} +x+3

The height is 3x

The base of the parallelogram, b, can be found by dividing the area by the height.

So, 'b' can be found as \frac{6x^{2}+x+3 }{3x}

In simplified form, we can write this as :

=> \frac{6x^{2} }{3x}+\frac{x}{3x}+ \frac{3}{3x}

=> 2x+\frac{1}{3}+\frac{1}{x}

Hence, base or 'b' is 2x+\frac{1}{3}+\frac{1}{x}

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