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3 years ago

10

The sum of 10 and a product of 7 and a number

1 answer:

NeX [460]3 years ago

8 0

The answer to your question, would be 7x + 10.

Hopefully this helps!

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Harman [31]

Wild guess?

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2 years ago

The sales tax on a one-half-carat diamond ring is $76. Find the purchase price of the ring (before tax) of the sales tax rate is

NISA [10]

So.. hmmm if we take "x" to be the 100% sale price before tax, $76 is really 9.5% of that

thus $\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
76&9.5\\
x&100
\end{array}\implies \cfrac{76}{x}=\cfrac{9.5}{100}$

solve for "x"

8 0

3 years ago

Solve: 2 In 3 = In(x - 4)<br><br><br> a) x=9 <br><br> b) x= 10<br><br> c) x=13

pogonyaev

Answer:

C) 13........................

5 0

3 years ago

Read 2 more answers

a class conduct a survey of 1000 students 6% of the students have forgotten their locker combinations how many students have for

solong [7]

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3 0

2 years ago

Which expressions have a value of 16/81? Check all that apply.

lana [24]

Which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

Answer:

First and last option is correct.

$(\frac{2}{3})^{4}=\frac{16}{81}$

$(\frac{4}{9})^{2}=\frac{16}{81}$

Step-by-step explanation:

Given:

There are four options.

(2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

We need to check all given options for value of 16/81.

Solution:

Using rule.

$(\frac{a}{b})^{n}=\frac{a^{n}}{b^{n}}$

Solve for option $(\frac{2}{3})^4$ .

$(\frac{2}{3})^{4}=\frac{2^4}{3^4}=\frac{2\times 2\times 2\times 2}{3\times 3\times 3\times 3}=\frac{16}{81}$

Solve for option $(\frac{16}{3})^4$ .

$(\frac{16}{3})^{4}=\frac{16^4}{3^4}=\frac{16\times 16\times 16\times 16}{3\times 3\times 3\times 3}=\frac{65536}{81}$

Solve for option $(\frac{4}{81})^2$ .

$(\frac{4}{81})^{2}=\frac{4^2}{81^2}=\frac{4\times 4}{81\times 81}=\frac{16}{6561}$

Solve for option $(\frac{4}{9})^2$ .

$(\frac{4}{9})^{2}=\frac{4^2}{9^2}=\frac{4\times 4}{9\times 9}=\frac{16}{81}$

Therefore, expression $(\frac{2}{3})^4$ and $(\frac{4}{9})^2$ have a value of $\frac{16}{81}$ .

6 0

3 years ago