Question

Please help!!!! Write the equation of the circle in general form. Show all your work

Answer 1

Let's first gather all the information we have:

 $\rm\hookrightarrow Center: (-3, 2)\\\rm \hookrightarrow Radius: 5$

Let's put that into standard form $(x-h)^2+(y-k)^2 =r^2$

• (h, k): center's coordinate
• r: radius

              $\rm \hookrightarrow Equation: (x+3)^2+(y-2)^2 = 5^2$

To put that equation into general form:

 ⇒ expand all the quadratics on one side and move the radius squared

      to the same side as the quadratics

           $(x+3)^2+(y-2)^2 = 25\\x^2+6x+9+y^2-4y+4=25\\x^2+y^2+6x-4y-12=0$

Answer: x² + y² + 6x - 4y - 12 = 0

Hope that helps!

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