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3 years ago

Locate√3 on number line and jusitify

Mathematics

1 answer:

alekssr [168]3 years ago

8 0

Root3 would be between 1 and 2 on the number line. This is known because 1 squared is 1, and 2 squared is 4.

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Given h(x)=-x-4, find h (-6)

Mumz [18]

2

explanation:

h(x)= -x-4

h(-6) = -(-6)-4
h(-6) = 6-4
h(-6) = 2

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3 years ago

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A sports ball has a diameter of 16 cm. Find the volume of the ball.

Yuliya22 [10]

Answer:

4/3 pi radius cubed

Step-by-step explanation:

4/3 pi x (8x8x8)

512 x 4/3 pi

2144.660585

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3 years ago

Given the domain -4,0,5 what is the range for 12x+6y=24

sweet [91]

Answer:

The range is -6, 4 , 12.

Step-by-step explanation:

If the domain is -4,0,5, x can only be -4 or 0 or 5.

Substitute each of these x-values into the equation 12x+6y=24. Then isolate to find the possible values of x.

Sub x for -4

12x+6y=24

12(-4)+6y=24

-48+6y=24

6y = 72

y = 12

Sub x for 0

12x+6y=24

12(0)+6y=24

6y = 24

y = 4

Sub x for 5

12x+6y=24

12(5)+6y=24

60 + 6y = 24

6y = -36

y = -6

The possible values of y are -6, 4 ,12 which is the range.

In set notation: R = {y|y=-6,4,12}

4 0

3 years ago

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What's the following rotational symmetries of oranges regular hexagon

Semmy [17]

Answer:

rotational symmetry of 60 degrees around the origin - yes

rotational symmetry of 120 degrees around the origin - yes

Step-by-step explanation:

A regular hexagon has 6 congruent angles

the the angles created on the line of symmetry are equal to 60 so the angle of rotational symmetry is 60 degrees.

The regular hexagon, like stated before, has 6 congruent angles so the order of symmetry is 6

Here is a visual from basic-matematics

6 0

3 years ago

What’s the answer to this question if your right I’ll keep giving you points

andreyandreev [35.5K]

$\huge\text{$m\angle O=\boxed{11^{\circ}}$}$

Since we know that all angles in a triangle add up to $180^{\circ}$ , we can solve for $x$ and substitute it back into $(x-5)^{\circ}$ to find $m\angle O$ .

$\begin{aligned}m\angle N+m\angle O+m\angle P&=180\\(5x-8)+(x-5)+(6x+1)&=180\end{aligned}$

Remove the parentheses and combine like terms.

$\begin{aligned}5x-8+x-5+6x+1&=180\\(5x+x+6x)+(-8-5+1)&=180\\12x-12&=180\end{aligned}$

Add $12$ to both sides of the equation.

$\begin{aligned}12x-12&=180\\12x&=192\end{aligned}$

Divide both sides of the equation by $12$ .

$\begin{aligned}x=16\end{aligned}$

Now that we have the value of $x$ , we can substitute it back into $(x-5)^{\circ}$ to find $m\angle O$ .

$\begin{aligned}m\angle O&=(x-5)\\&=16-5\\&=\boxed{11}\end{aligned}$

7 0

3 years ago

Locate√3 on number line and jusitify​

Locate√3 on number line and jusitify