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mina [271]
2 years ago
6

Select the correct answer. two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is labeled 4x

minus 1, side bc is labeled 4, side ac is labeled 5. in triangle cde, side cd is labeled 5, side de is labeled x plus 2, side ce is labeled 4. if geometry symbol represented as small triangle with three sides. abc geometry congruent symbol represented as two small horizontal parallel lines and a horizontal symbol s. geometry symbol represented as small triangle with three sides. dec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
Mathematics
1 answer:
Sidana [21]2 years ago
4 0

Hence, the value of x is 1.

<h2>What is length?</h2>

Length is defined as the measurement or extent of something from end to end. In other words, it is the larger of the two or the highest of three dimensions of geometrical shapes or objects.

<h3>How to solve?</h3>

It can be observed that the given 2 triangles are congruent.

we know, for congruent triangles, the length of corresponding sides is equal.

Hence,

       AB = DE

       4x - 1 = x + 2

       3x = 3

       x=1

Therefore, the value of x is 1.

to learn more about length: brainly.com/question/18077445

#SPJ4

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jarptica [38.1K]
<u>f(x) = x + 3</u>
f(2) = 2 + 3
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3 years ago
What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
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Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

=(x+a)(x+b)

now, we can multiply factor term

(x+a)(x+b)=x^2+(a+b)x+ab

now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

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we are given that

'a' and 'b' are integers

so, we can find all possible factors

15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

k=a+b

we can plug values

k=-1-15

k=-16

At (1\times 15):

k=a+b

we can plug values

k=1+15

k=16

At (-3\times -5):

k=a+b

we can plug values

k=-3-5

k=-8

At (3\times 5):

k=a+b

we can plug values

k=3+5

k=8

So, values of k are

k=-16,k=-8,k=8,k=16

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