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11Alexandr11 [23.1K]
3 years ago
7

Theresa has two brothers,Paul and Steve, who are both the same height. Paul says he is 16 inches shorter than 1 1/2 times Theres

a's height. Steve says he's 6 inches shorter than 1 1/3 times Theresa's height. If they're both right, how tall is Theresa ?​
Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

Theresa's height is 60 inches

Step-by-step explanation:

The given parameters are;

The height of Paul = The height of Steve

Paul's height = 1\dfrac{1}{2} times Theresa's height - 16 inches

Steve's height = 1\dfrac{1}{3} times Theresa's height - 6 inches

Let 'T' represents Theresa's height, we have;

Paul's height = 1\dfrac{1}{2} ×T - 16

Steve's height = 1\dfrac{1}{3} ×T - 6

Paul's height = Steve's height

Therefore;

1\dfrac{1}{2} ×T - 16 = 1\dfrac{1}{3} ×T - 6

1\dfrac{1}{2} ×T - 1\dfrac{1}{3} ×T = 10

#\dfrac{3}{2} ×T - \dfrac{4}{3} ×T = 10

\dfrac{1}{6} ×T = 10

T = 10 × 6 = 60

Theresa's height, T = 60 inches

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Step-by-step explanation:

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(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

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