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JulijaS [17]
3 years ago
9

Help ur boy out abcdefghijklmnopqrstuvwxyz

Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

  1. (-6, 10)
  2. (-10, 9)
  3. (-11, -6)
  4. (-5, 1)

Step-by-step explanation:

<em>(x,y) → (x-8, y+4)</em>

1. (2, 6)

(2-8, 6+4)

<u>(-</u><u>6, 10)</u>

2. (-2, 5)

(-2-8, 5+4)

<u>(-10, 9)</u>

3. (-3, -10)

(-3-8, -10+4)

<u>(-11, -6)</u>

ídk man u should connect it to <u>(11, -7)</u> since it's the only choice closest to the right answer, but If u can write the correct then write this. there's prolly an error in that quiz ídk

4. (3, -3)

(3-8, -3+4)

<u>(-5, 1)</u>

<u> </u>still not in the choices nanii but <u>(5, -14)</u> is the only choice left and also the closest, and even if u use calculator the correct answer is still (-5, 1). sigh, I hope this helper at least

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The length of a rectangle is 2 cm more than four times the width. If the perimeter of the rectangle is 84 cm, what are its dimen
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Answer:

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Step-by-step explanation:

Let

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y----> the width of the rectangle

we know that

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84=2(x+y)

42=x+y ----> equation A

x=4y+2 -----> equation B

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The 65 students in a classical music lecture class were polled, with the following results: 37 like Wolfgang Amadeus Mozart 36 l
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Answer:

a) 25

b) 30

c) 10

d) Not Mozart, 6

e) 2

Step-by-step explanation:

We use a Venn Diagram to solve this question.

I am going to say that:

A are the students who like Mozart.

B are the students who like Beethoven

C are the students who like Haydn.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a are those who only like Mozart, (A \cap B) are those who like Mozart and Beethoven, (A \cap C) are those who like Mozart and Haydn and (A \cap B \cap C) are those who like all three of them.

By the same logic, we have that:

B = b + (A \cap B) + (B \cap C) + (A \cap B \cap C)

C = c + (B \cap C) + (A \cap C) + (A \cap B \cap C)

We start finding these values from the intersection:

8 like all three composers

This means that A \cap B \cap C = 8

14 like Beethoven and Haydn

This means that:

(B \cap C) + (A \cap B \cap C) = 14

So

B \cap C = 6

21 like Mozart and Haydn

This means that:

(A \cap C) + (A \cap B \cap C) = 21

Then

A \cap C = 13

14 like Mozart and Beethoven

This means that:

(A \cap B) + (A \cap B \cap C) = 14

A \cap B = 6

31 like Franz Joseph Haydn

This means that C = 31. So

C = c + (B \cap C) + (A \cap C) + (A \cap B \cap C)

31 = c + 6 + 13 + 8

c = 4

36 like Ludwig van Beethoven

This means that B = 36

So

B = b + (A \cap B) + (B \cap C) + (A \cap B \cap C)

36 = b + 6 + 6 + 8

b = 16

37 like Wolfgang Amadeus Mozart

This means that A = 37. Then

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

37 = a + 6 + 13 + 8

a = 10

a. exactly two of these composers?

(A \cap B) + (A \cap C) + (B \cap C) = 6 + 13 + 6 = 25

b. exactly one of these composers?

a + b + c = 10 + 16 + 4 = 30

c. like only Mozart?

a = 10

d. like Beethoven and Haydn, but not Beethoven?

I will use not Mozart.

So B \cap C = 6

Not Mozart, 6.

e. like none of these composers?

At least 1:

(A \cup B \cup C) = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 10 + 16 + 4 + 6 + 13 + 6 + 8 = 63

The total is 65

So 65 - 63 = 2 like none of these composers

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