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2 years ago

What is the range of f?

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

4 0

Answer: $[-3,7]$

Step-by-step explanation:

The range of a function is the set of y-values

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What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2

sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let $a_{1}=-2$

$a_{2}=-1$

$a_{3}=a_{1}-a_{2}$

$=-2-(-1)$

$=-2+1$

Therefore $a_{3}=-1$

$a_{4}=a_{2}-a_{3}$

$=-1-(-1)$

$=-1+1$

Therefore $a_{4}=0$

Similarly we have $a_{5}=-1$ , $a_{6}=1$ , $a_{7}=-2$

The general form to the given pattern is

$a_{n}=a_{n-2}+a_{n-1}$ for $n={\{1,2,3,4,5,6,7,8,9,10}\}$

Therefore to find the $a_{8},a_{9},a_{10}$

Put n=8 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{8}=a_{8-2}-a_{8-1}$

$=a_{6}-a_{7}$

$=1-(-2)$

$a_{8}=3$

Put n=9 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{9}=a_{9-2}-a_{9-1}$

$=a_{7}-a_{8}$

$=-2-(3)$

$a_{9}=-5$

Put n=10 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{10}=a_{10-2}-a_{10-1}$

$=a_{8}-a_{9}$

$=3-(-5)$

$a_{10}=8$

Therefore the next 3 numbers are 3,-5,8

4 0

3 years ago

Landon owns a hybrid SUV that can travel 400 miles on a 15 gallon tank of gas. Determine how many miles he can travel in 6 gallo

arlik [135]

Set this up as a proportion.

400/15 = x/6

Solve for x.

I just hope to help! :)

8 0

3 years ago

QUESTION ON PIC THX!!!!

Maru [420]

Answer:

Step-by-step explanation:

The 3 angles have to add to 180

180 - 69 - 50 = 61

6 0

3 years ago

Read 2 more answers

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

4 years ago

What is the decimal multiplier to increase by 99%?

ipn [44]

Answer:

1.99

Example:

Increase 10 by 99%. 99% of 10 is 9.9 so increased value would be 10 + 9.9 = 19.9

10 x 1.99 = 19.9 ... same answer

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers