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saul85 [17]
2 years ago
12

What is the domain of the following function: y=x^-5 + (x-1)

Mathematics
1 answer:
insens350 [35]2 years ago
7 0

Answer:

Step-by-step explanation:

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Which equation represents the nth term of the sequence {2,1,-4,-7...}.
Gemiola [76]

Answer:

n=-3n+5

Step-by-step explanation:

8 0
3 years ago
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A bag contains 666 red balls, 444 green balls, and 333 blue balls. If we choose a ball, then another ball without putting the fi
Ronch [10]

Answer:

P(GR)=\frac{2}{13}

Step-by-step explanation:

Number Of Red Balls=6

Number Of Green Balls=4

Number Of blue Balls=3

Total Number Of Balls=6+4+3=13

Notice that the two balls are picked without replacement. In this case, the total number of balls always decreases.

P(first ball will be green and the second will be red)

=\dfrac{4}{13} X \dfrac{6}{12}  \\=\dfrac{2}{13}

4 0
3 years ago
Read 2 more answers
Order the numbers so the steps are accurate. Thanks!
kifflom [539]
<span><span>1. </span></span>Draw a line segment of length s. Label its endpoints PPP and QQQ.<span><span>
</span><span>2. </span></span>Extend the line segment past QQQ.<span><span>
</span><span>3. </span></span>Erect the perpendicular to PQ−→−normal-→PQ {PQ} at QQQ
<span><span>4. </span></span>Using the line drawn in the previous step, mark off a line segment of length sss such that one of its endpoints is QQQ. Label the other endpoint as RRR.<span><span>
</span><span>5. </span></span>Draw an arc of the circle with center PPP and radius PQ normal PQ\ {PQ}.<span><span>
</span><span>6. </span></span>Draw an arc of the circle with center RRR and radius QR normal QR\overline{QR} to find the point SSS where itintersects the arc from the previous step such that S≠QSQS\neq Q.<span><span>
</span><span>7. </span></span>Draw the square PQRSPQRSPQRS.
4 0
3 years ago
Write each improprt fractionn as a mixed number or a whole number
Citrus2011 [14]
2 divided into 7 gives 3 with remainder 1  
so as a mixed number 7/2  = 3 1/2
7 0
4 years ago
Read 2 more answers
What is the product of 3 square root 7 and 17 square root 14 in simplest radical form ​
Aleks [24]

3 \sqrt{7}  \times 17 \sqrt{14}

This is the problem that we need to solve. The best way to get about it is to first:

  1. Multiply the constant numbers (3 and 17). 3×17 is 51.
  2. Next multiply the radicals.
  3. \sqrt{7}  \times   \sqrt{14}  =  \sqrt{7 \times 14}  =  \sqrt{108}
  4. Simplify the squareroot of 108 since it is 49 times 2. It would be equal to 7 squareroots of 2.
  5. Our final answer would be:
  6. 51 \times  7\sqrt{2}  = 357 \sqrt{2}
  7. 51 x 7 is 357, so the answer above is right.

The skills needed are multiplication, mulitplication of radicals, and simplifying radicals, so if you want to review anything use these as reference.

Hope you understood and have a nice day!!

3 0
3 years ago
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