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yaroslaw [1]
3 years ago
9

If the complex number x = 3 + bị and x/2 = 13, which is a possible value of b?

Mathematics
1 answer:
Virty [35]3 years ago
7 0

Answer:

23

Step-by-step explanation:

Given,

x = 3 + bị

Again,

x ÷ 2 = 13

Multiplying both the sides by 2, we can get.

(x ÷ 2) × 2 = 13 × 2

or, x = 26

As we find the value of x, we can now complete the complex number which is b.

x = 3 + bị

Putting the value of x, we can get,

26 = 3 + bi

or bi = 26 - 3

or, b = 23.

Therefore, the possible value of b = 23.

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