Answer:
The intercepts are -5 and 2
Step-by-step explanation:
Using the zero product property
f(x)=(x+5)(x-2)
0 =(x+5)(x-2)
0 = (x+5) 0=(x-2)
x = -5 x = 2
The intercepts are -5 and 2
Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
Answer:
2
Step-by-step explanation:
Answer:
73
Step-by-step explanation:
you write 12 instead of b
4.428571
I know because I googled it
