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Viefleur [7K]
3 years ago
11

Please help, I I beg you please

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

<em>The volume of the cube is </em> \mathit{\frac{27}{z^3x^{9}}} <em>cu in.</em>

Step-by-step explanation:

<u>The Volume of a Cube</u>

Let's have a cube of side length a. The volume of the cube is:

V=a^3

The cube of the image has a side length of

\displaystyle a=\frac{3x^{-3}}{z}\ inches

Simplifying the expression of the base by converting the negative exponent in the numerator to the denominator:

\displaystyle a=\frac{3}{zx^{3}}\ inches

Now find the volume:

\displaystyle V=\left(\frac{3}{zx^{3}}\ inches\right)^3

Applying the exponents:

\displaystyle V=\frac{3^3}{z^3x^{9}}\ inches^3

\displaystyle V=\frac{27}{z^3x^{9}}\ inches^3

The volume of the cube is \mathbf{\frac{27}{z^3x^{9}}} cu in.

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An inverted pyramid is being filled with water at a constant rate of 25 cubic centimeters per second. The pyramid, at the top, h
UNO [17]

Answer:

\frac{225}{16} cm/s

Step-by-step explanation:

We are given that

\frac{dV}{dt}=25cm^3/s

Side of base=4 cm

l=w=4 cm

Height,h=12 cm

We have to find the rate at which the water level rising when the water level is 4 cm.

Volume of pyramid=\frac{1}{3}lwh=\frac{1}{3}l^2h

\frac{l}{h}=\frac{4}{12}=\frac{1}{3}

l=\frac{1}{3}h

Substitute the value

V=\frac{1}{27}h^3

Differentiate w.r.t t

\frac{dV}{dt}=\frac{3}{27}h^2\frac{dh}{dt}

Substitute the values

25=\frac{1}{9}(4^2)\frac{dh}{dt}

\frac{dh}{dt}=\frac{25\times 9}{16}=\frac{225}{16} cm/s

5 0
3 years ago
Please help with this problem ​
Svetlanka [38]
The answer should be 25.64$
You multiple that by 8% and then what you get out of it you add on to what you got as the total .
6 0
3 years ago
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Can someone help me with this please
zavuch27 [327]

Answer:

8×

Step-by-step explanation:

you just add 7×+1 and the answer will be 8×

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2 years ago
What are the coordinates of the vertex of the parabola described by the
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Step-by-step explanation:

please type the question properly

3 0
3 years ago
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Aiko jumped rope for an amazing 20 minutes. She stoped at 8:05. When did she start jumping?
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If she stopped at 8;05, and she started 20 minutes earlier, just imaging a clock at 8:05 and turn back time 20 minutes.

Five minutes would be 8:00, ten minutes is 7:55, fifteen minutes is 7:50, and twenty minutes is 7:45. This, she started at 7:45
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