All categories

4 years ago

What is the simplified form of x-2 over x2+x-6 divided x2+5x+4 over x+4

Mathematics

2 answers:

pychu [463]4 years ago

7 0

Answer:

$1/((x+3)*(x+1))$

Step-by-step explanation:

We can write the expression as:

$((x-2)/(x^2+x-6))/((x^2+5*x+4)/(x+4))$

We can write the term as a single division by multiplying the terms in numerator by the inverse on the terms in the denominator:

$((x-2)/(x^2+x-6))*((x+4)/(x^2+5*x+4)/)$

$((x-2)*(x+4))/((x^2+x-6)*(x^2+5*x+4))$

We can simplfy the denominator terms as:

$x^2+x-6=(x+3)*(x-2)$

$x^2+5*x+4=(x+4)*(x+1)$

Therefore (x-2) and (x+4) in the numerator and denominator cancels out and we are left with:

$1/((x+3)*(x+1))$

skad [1K]4 years ago

5 0

X-2 over x2+x-6 divided x2+5x+4 over x+4 requires 2 factoring, canceling like factors, and inverting the divisor and multiplying.

(x-2) over (x+3)(x-2) divided by (x+4)(x+1) over (x+4) after factoring twice

canceling like factors
1 over (x+3) divided by (x+1) over 1
invert denominator and multiply

answer 1 over (x+3)(x+1)

You might be interested in

A pound of chocolate costs 8 dollars. Kala buys p pounds. Write an equation to represent the total cost c that Kala pays.

ASHA 777 [7]

Answer:

8p=c

Step-by-step explanation:

For questions like this, it isn't asking for a numerical answer or anything complicated. It's mainly just using common sense and figuring out what you would do if you had actual numbers instead of variables. You would multiply the amount of pounds (p) by the cost per pound of $8, and that would be your answer (c). I hope I could help.

7 0

3 years ago

Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is

Simora [160]

The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: $A=s^2$
Were
$A$ is the area in square kilometers
$s$ is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so $s=0.9$ . Lets replace that value in our formula to find $A$ :
$A=(0.9)^2$
$A=0.81$

Now, to find the population density of the filed, we are going to use the population density formula: $P_{d}= \frac{I}{A}$
where
$P_{d}$ is the population density in in burrows per square kilometer
 $I$ is the number of burrows
$A$ is the are of the field
We know that $I=1980$ and $A=0.81$ , so lets replace those values in our formula:
$P_{d}= \frac{1980}{0.81}$
$P_{d}=2444.4$

We can conclude that the density of prairie dog burrows is approximately 2444 burrws per square kilometer.

5 0

3 years ago

Given ; 2(10-13x)+9x=-34x+60

rewona [7]

Try comparing your solution with the following:

Solution:

$2(10-13x)+9x=-34x+60\\(20-26x)+9x=-34x+60\\20-26x+9x=-34x+60\\20-17x=-34x+60\\20-60=-34x+17x\\-40=-17x\\x=\frac{40}{17}$