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Yuri [45]
3 years ago
7

Which expressions are equivalent to 0.5*m*n*4 2(m+n) 0.5m + 4n None of the above

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0
0.5*m*n*4=0.5*4*m*n = 2*m*n = 2mn

2(m+n) = 2m + 2n ≠ 2mn

0.5m + 4n ≠ 2mn

The answer is None of the above
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Answer:

C

Step-by-step explanation:

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1 year ago
There are three executives in an office, ages 56, 57, and 58. If a 57-year-old executive enters the room, the
vova2212 [387]

Answer:

option (c) The mean age will stay the same but the variance will decrease

Step-by-step explanation:

Case I: For 3 executives of ages 56, 57 and 58

Number of executives, n = 3

Mean = \frac{\textup{56 + 57 + 58 }}{\textup{3}}

or

Mean = 57

Variance = \frac{\sum{(Data - Mean)^2}}{\textup{n-1}}

or

Variance = \frac{(56 - 57)^2+(57-57)^2+(58-57)^2}{\textup{3-1}}

or

Variance = \frac{1+0+1}{\textup{2}}

or

Variance = 1

For Case II: For 4 executives of ages 56, 57, 58 and 57

Number of executives, n = 4

Mean = \frac{\textup{56 + 57 + 58 + 57 }}{\textup{4}}

or

Mean = 57

Variance = \frac{\sum{(Data - Mean)^2}}{\textup{n-1}}

or

Variance = \frac{(56 - 57)^2+(57-57)^2+(58-57)^2+(57-57)^2}{\textup{4-1}}

or

Variance = \frac{1+0+1+0}{\textup{3}}

or

Variance = 0.67

Hence,

Mean will remain the same and the variance will decrease

Hence,

The correct answer is option (c) The mean age will stay the same but the variance will decrease

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