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Answer: A = 198.6cm²
Step-by-step explanation: The figure includes two semi circles on both ends. These can be solved as a whole circle with a diameter of 10cm because each semi circle is 5cm.
r = 10/2= 5cm
Area of circle:
A = πr²
A = 3.142*5²
A = 3.142*25
A = 78.55
A = 78.6cm²
The remaining section of the shape is a rectangle with a length of 12cm.
To get this, you subtract 10 from 22 because each semi circle is 5cm which adds up to 10cm.
The rectangle has a width of 10cm.
Area of rectangle:
A = lw
A = 12*10 = 120cm²
The total area of the shape:
A = 120 + 78.6
A = 198.6cm²
Answer: 907.92 ft²
Step-by-step explanation:
1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:
Where r is the radius of the circle.
2. You know the radius of the circle B, therefore, when you susbtitute it into the formula, you obtain that the area of the circle B is:
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Here's the factorization of the equation
f(x) = [ (x+4)(2x-1) ] / [ (x-1)(x^2+x+1) ]
<u>Domain</u>
The domain of a function is the set of input or argument values for which the function is real and defined.
- function domain : x < 1 or x > 1
<u>Range
</u><u />Resulting f(x) values: all Real Numbers<u>
</u>
<u>Roots
</u>x = 1/2 & -4
<u>Axis interception points</u>
x-axis: (1/2, 0) , (-4, 0)
(y-axis): (0, 4)
<u>Asymptotes</u>
Vertical: x = 1
Horizontal: y = 0