(1/6)(36/100)<4 - (2/10)
6/100 < 38/10
3/50 < 190/50
true
Answer:
64.
Step-by-step explanation:
Sigma notation is ∑48(1/4)^(n-1).
Upper limit = a1 / (1 - r) where a1 = initial population and r = common ratio.
So it is 48 / (1 - 1/4)
= 48 / 3/4
= 48 * 4/3
= 64.
Answer:
0.625
Step-by-step explanation:
Given :
Ambell company uses or procures batteries from two manufacturers.
The life of a battery in critical tool is at = 32 hours
Ambell uses 70% of its batteries from manufacturer 1 and out of that 90% batteries lasts for about 40 hours.
Similarly, 75% of the batteries procured from the manufacturer 2 lasts for about 40 hours.
Therefore, the probability that a battery is form manufacturer 1 is :

= 0.625
Answer:
h-15=42 ~~~~ Brainliest would be nice :') thank u!
Step-by-step explanation: