Answer:
hey,
ur question is wrong,
base of triangle can never be longer than hypotenuse,and you have told base is twice of hypotenuse,
if hypotenuse is twice of base, then solution is give below, in picture,
and answer is 1/2
Answer:
she earned $288.75 in commissions
Step-by-step explanation:
Get unknowns on one side and know on other side.
Divide both sides by -2
X= -7
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
The answer i 9
Step-by-step explanation:
If the ball bounces 2/3 of the height of 9, and a 1/3 of 9 is 3, then 6 is the answer.
