<span>y = 5x – 2 y = 5(11) – 2 y = 55 – 2 = 49
Remember, the values of the range are the values of y that we obtained above.
Therefore, the values of the range are {0.5,49).</span>
B x b x b x b x b x b x b x b x b x b x b x b x b x b x b
Answer:
The answer is 84.08
Step-by-step explanation:
1) line up the decimal points
2) add it up like any addition problem
3) Place the decimal point right under the placement of the decimal point of the problem
To find a perpendicular line you first need to see the equation in slope intercept form. To do that you need to solve for y.
2x - 5y = 20 ---> subtract 2x from both sides
-5y = -2x + 20 ---> divide by -5
y = 2/5x - 4
Now that you have this, note that a perpendicular line has opposite and reciprocal slope. Since the slope in our equation is 2/5, that means the new line will have -5/2 slope. So we use the point given and the slope to find the y intercept.
y = mx + b
-8 = -5/2(7) + b ---> multiply
-8 = -35/2 + b ---> add 35/2 to both sides
19/2 = b
Now use our new slope and new y intercept to write the new equation.
y = -5/2x + 19/2
Answer:
-5
Step-by-step explanation:
Moving all terms of the quadratic to one side, we have
.
A quadratic has one real solution when the discriminant is equal to 0. In a quadratic 
, the discriminant is 
.
(The discriminant is more commonly known as 
, but I changed the variable since we already have a 
in the quadratic given.)
In the quadratic above, we have 
, 
, and 
. Plugging this into the formula for the discriminant, we have
.
Using the distributive property to expand and simplifying, the expression becomes
Setting the discriminant equal to 0 gives
.
We can then solve the equation as usual: first, divide by 2 on both sides:
.
Squaring both sides gives
,
and subtracting 5 from both sides, we have
