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12345 [234]
2 years ago
14

The cube of the sum of a number and 3.

Mathematics
1 answer:
Verdich [7]2 years ago
3 0
The answer is 3! You got this!
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A pair of perpendicular lines intersect at the point (5,9). Write
maw [93]

Answer:

The equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18

Step-by-step explanation:

The coordinates of the point of intersection of the two lines = (5, 9)

The coordinates of a point on one of the two lines, line 1 = (-4, 4)

The slope of a line perpendicular to another line with slope, m = -1/m

Therefore, we have;

The slope, m₁, of the line 1 with the known point = (9 - 4)/(5 - (-4)) = 5/9

Therefore, the slope, m₂, of the line 2 perpendicular to the line that passes through the point (-4, 4) = -9/5

The equation of the line 2 is given as follows;

y - 9 = -9/5×(x - 5)

y - 9 = -9·x/5 + 9

y =  -9·x/5 + 9 + 9

y = -9·x/5 + 18

Therefore, the equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18.

6 0
3 years ago
Find 5/6(−4 x 2/7). Write your answer in simplest form.
shtirl [24]
-0.96
If you look up that exact equation on google you get -0.952380952 and you just round it to get -0.96
4 0
3 years ago
Read 2 more answers
A party rental company has chairs and tables for rent. The total cost to rent 4 chairs and 8 tables is $89 . The total cost to r
puteri [66]
Let C = cost to rent each chairLet T = cost to rent each table

 4C + 8T = 73
2C + 3T = 28 
Multiply the 2nd equation by (-2) and then add the equations together 

  4C + 8T = 73
-4C - 6T = -56
 2T = 17T = 17/2 = 8.5

 Plug this in to the 1st equation to solve for C
 4C + 8(17/2) = 73
4C + 68 = 73
4C = 5C = 5/4 = 1.25
 So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50 
7 0
3 years ago
Read 2 more answers
can someone help me with this? this is algebra 2 question and please show me all work (orderd pair, vertex, graph ect..)
Andrews [41]
To find the maximum height you need to find the vertex:(h,k)  
Your equation is in vertex form a(x-h)+k and the vertex is (h,k) where k is the maximum height and the h is the distance it went to reach the maximum height.
k=6 so the kangaroo's maximum height is 6 feet.

To find how long is the kangaroo's jump, take a look at the graph. You will notice that the parabola ends at the distance the kangaroo jumped. You will also see that it is the one of the x-intercepts. 

 
 -.03(x-14)^2+6=0
-.03(x-14)^2+6-6=0-6
-.03(x-14)^2=-6
-.03/-.03(x-14)=-6/-.03
(x-14)^2=200
[(x-14)^2]^.5=200^.5
x-14=(200)^.5
x-14+14=(200)^.5+14
x≈28.14 feet
The kangaroo jumped a distance of 28.14 feet.

You will notice that the square root of a number gives you two solutions a positive and a negative one. The other solution is -.14, which we know distance is not negative so we do not use that solution. Also, I used the ^.5 instead of using the square root. It is the same. 


8 0
4 years ago
Find the mass of the triangle with vertices (1; 0; 0), (0; 2; 0), (0; 1; 1) if the density function is given by (x; y; z)
Luda [366]

Answer:

=\frac{17}{3}

Step-by-step explanation:

Density of a function is \rho(x,y)=x^{2} +y^{2}

I have drawn the right angle triangle for visualization

equation for the line passing through (1,0) and (0,4) is

\frac{y}{4} =\frac{x-1}{-1}

y=4-4x

=$$\int_{0}^1\int_{0}^{4-4x} (x^{2}+y^{2})dydx$$

=$\int_{0}^{1}(x^{2}+\frac{y^{3} }{3})dx$  

=$\int_{0}^{1}(x^{2}(4-4x)+\frac{1}{3}(4-4x)^{3} )dx$

=$\int_{0}^{1}(\frac{-76}{3}x^{3} +68x^{2}-64x^{}+\frac{64}{3}  )dx$

==(\frac{-76}{3} \frac{x^{4} }{4})+\frac{68}{3}x^{3}-32x^{2}+\frac{64}{3}x^{})  

=\frac{17}{3}

3 0
3 years ago
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