Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
Answer:
Pythagoras theorem.
hypotenuse²=height²+base²
x²=15²+12²
x²=225+144
x²=329
x=329½
x=19.20
Answer:
Step-by-step explanation:
We are given the inequality x < -2 or x ≥ 3 in which the problem asks to determine the domain of the inequality. In this case, this means numbers less than -2 or numbers equal to 3 and greater than three. The relation that illustrates the previous statement is B. x e(-∞,-2) n[3,∞)
That is 2(1/7 + 1/2)
= 2( 2/14 + 7/14)
= 2 * 9/14
= 18/14 = 9/7 units ( or 1 2/7 units)
