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Ivahew [28]
2 years ago
14

The number of users on a website is 3700 and is growing exponentially at a rate of

Mathematics
1 answer:
jek_recluse [69]2 years ago
8 0

Answer:

3034 I think

Step-by-step explanation:

3034 I think because if u multiply 3700 times 0.82 give you 3034

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Lesechka [4]
I think that it’s 16 probably
6 0
2 years ago
Using the quadratic formula to solve 7x2 -x = 7, what are the values of x?
Sunny_sXe [5.5K]

Answer:

x=-7

Step-by-step explanation:

7x2-x=7

7x2=14.

14-x=7

When you finished the last step, you will subtract 14 to both sides.

14-x=7

14-14-x=7-14

this will cancel out the 14 on the left.

And will leave you with:

-x=7-14

7-14 is -7.

and this will get you to

-x=-7

To finish this off, you have to turn the negative x/variable, into a positive x/variable.

So, you will divide both sides of the equation by the same term.

-x = -7

into

\frac{-x}{1} =\frac{-7}{1}

and it will be -7.

I hope this helps      :)

8 0
3 years ago
What is the volume of the given picture below? ( HELP PLEASE )
AlexFokin [52]
It's 904.78.

The formula for the volume of a sphere is 4/3(pi)r^3. The diameter is 12. Half it to get the radius, which is 6. Plug 6 into the formula. The result is 904.77868.
4 0
2 years ago
What ratio can we say are equivalent to 2:9 how do you get the answer explain to me
Ulleksa [173]
Ratio equivalent to 2:9 is 4:18, 6:27

If you multiply the same number to both numbers, the ratio would always be the same. 
5 0
3 years ago
Confusion...help please
kifflom [539]

Given:

In triangle KLM, KL = 123 cm and measure of angle K is 35 degrees.

To find:

The length of the side KM to the nearest tenth of a centimeter.

Solution:

In a right angle triangle,

\cos \theta =\dfrac{Base}{Hypotenuse}

In the given right triangle KLM,

\cos K=\dfrac{KM}{KL}

\cos (35^\circ)=\dfrac{KM}{123}

0.819152=\dfrac{KM}{123}

Multiply both sides by 123.

0.819152\times 123=KM

100.755696=KM

KM\approx 100.8

The measure of side KM is 100.8 cm.

Therefore, the correct option is (2).

8 0
2 years ago
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