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3 years ago

HELP PLEASE!!!!!! AND TYYY

Mathematics

1 answer:

MatroZZZ [7]3 years ago

8 0

Answer:

17cm Squared

Step-by-step explanation:

Get the area of the whole triangle, then the area of the white part. Then subtract the white from the whole area

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Can someone help me out my grade are bad

posledela

Answer:

a. 0.4 and 0.5

b. 0.46

Step-by-step explanation:

i don't know if this right, so lmk

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3 years ago

3. Which disease is caused by bacteria found in soil that infect deep wounds?

skad [1K]

Tetanus is caused by toxin made by spores of bacteria

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3 years ago

Which logarithmic graph can be used to approximate the value of y in the equation 2^y = 3 ( graphs attached)

alekssr [168]

Neither of the given graphs is the answer for your question... Since 2^y=3, y=log_2(3), by definition of log. You can see that y is a fixed value, so the graph must be a horizontal line. The value of y doesn't change as x change, since x doesn't even appear in the equation.

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3 years ago

saveliy_v [14]

$26.60 would be you’re answer i believe

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3 years ago

Evaluate the surface integraliintegral.gifSF � dSfor the given vector field F and the oriented surface S. In other words, find t

ehidna [41]

Looks like the paraboloid has equation

$z=2-x^2-y^2$

and $S$ is the part of this surface with $0\le x\le1$ and $0\le y\le1$ . Parameterize $S$ by

$\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(2-u^2-v^2)\,\vec k$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=2u\,\vec\imath+2v\,\vec\jmath+\vec k$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S$

$\displaystyle=\int_0^1\int_0^1(uv\,\vec\imath+v(2-u^2-v^2)\,\vec\jmath+u(2-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv$

$\displaystyle=\int_0^1\int_0^1(2u^2v+(2v+1)u(2-u^2-v^2))\,\mathrm du\,\mathrm dv=\boxed{\frac{293}{180}}$

8 0

3 years ago