Answer:
Probability that event will have both red marbles will be 2.3% or 0.023.
Step-by-step explanation:
Given:
Total red marbles=5
Total blue marbles=25
Total number of marbles =30
To Find:
The probability that both are red without replacement of marbles.
Solution:
Now
Total sample space is 30 and total red marbles are 5
For a event that getting red marble probability is ,
=Total red marbles /total marbles.
=5/30
=1/6
So probability if getting red marble is 1/6
<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>
In second chance probability if getting red marble will be
=total red marbles present/total marbles remaining
=4/29
Now ,
The required probability will be getting both at a time
i.e probability getting red AND red marble so here AND operator which means multiple both the probability.
Probability both will have red =1/6*4/29
=4/(29*6)=2/(29*3)
=0.022988
=0.023
=2.3 %
Answer: 2 and three-fourths (2 3/4)
Step-by-step explanation:
11 * 1/4
1/4 = 0.25
0.25 * 11 = 2.75
.75 = 3/4
2.75 = 2 3/4
Answer:
rational
Step-by-step explanation:
I believe this question logically tells us to find the value of w. The two equations are already equated. Since there is 1 unknown and 1 equation, the system is solvable. The solution is as follows:
5/(6w+21) = -1/3(2w - 9)
5/(6w+21) = -1/(6w - 27)
Cross multiplying the terms:
5(6w - 27) = -1(6w +21)
30w - 135 = -6w - 21
30w + 6w = -21 + 135 = 114
36w = 114
w = 114/36
w = 19/6 or 3.167
Answer:
A
Step-by-step explanation:
d = 0.5 * t There are no conversions. You just substitute the value for t.
d = 0.5 * 27.9
d = 13.95 which is A
