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Tamiku [17]
1 year ago
14

If the function y = sinx is transformed to y = 3 sine (two-thirds x), how do the amplitude and period change?

Mathematics
1 answer:
Marina86 [1]1 year ago
6 0

Change in Amplitude is 2

Change in Period is π

Transforming sin(x) to 3sin(\frac{2x}{3})

y = a(sin(bx+c)) + d

Where, a is Amplitude and \frac{2}{b}π is period

Amplitude of sin(x) =1

Period of sin(x) = 2π

Amplitude of 3sin(\frac{2x}{3}) = 3

Period of 3sin(\frac{2x}{3}) = \frac{2}{\frac{2}{3}}*π = 3π

Change in Amplitude = 3sin(\frac{2x}{3}) - sin(x)

                                    = 3 - 1

                                    = 2

Change in Period = 3sin(\frac{2x}{3}) - sin(x)

                              = 3π - 2π

                               = π

To learn more about Amplitudes and Periods visit:

brainly.com/question/23713359

#SPJ4

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Plz help<br> Don’t know which one it is?
ddd [48]

Answer:

 First option  6^\frac{1}{6} is the correct answer.

Step-by-step explanation:

Let us consider each part, we have number 6 inside all the roots.

First we have to find cube root of 6.

                    \sqrt[3]{6} =6^\frac{1}{3}

Now we have to find square root of this value.

                   \sqrt{6^\frac{1}{3}  } =(6^\frac{1}{3} )^\frac{1}{2} =6^\frac{1}{6}

So, first option  6^\frac{1}{6} is the correct answer.

3 0
3 years ago
How to convert base two to base three​
sladkih [1.3K]

Consider this example: say we want to convert <em>x</em> = 11 0101 1001₂ to base 3.

The binary expansion of <em>x</em> is

<em>x</em> = 1×2⁹ + 1×2⁸ + 1×2⁶ + 1×2⁴ + 1×2³ + 1×2⁰

which in base 10 reduces to

<em>x</em> = 512 + 256 + 64 + 16 + 8 + 1 = 857

Recall the first several powers of 3:

3⁰ = 1; 3¹ = 3; 3² = 9; 3³ = 27; 3⁴ = 81; 3⁵ = 243; 3⁶ = 729

Now it's a matter of computing quotients and remainders. Pick the largest power of 3 that fits into the target number, then check the remainder and repeat.

• How many times does the 729 go into 857? 1 time, and it leaves a remainder of 128, or

857 = 1×729 + 128 = 1×3⁶ + 128

• How many times does 81 go into 128? Also 1 time, so

128 = 1×81 + 47 = 1×3⁴ + 47

• How many times does 27 go into 47? Also 1 time,

47 = 1×27 + 20 = 1×3³ + 20

• How many times does 9 go into 20? 2 times,

20 = 18 + 2 = 2×9 + 2 = 2×3² + 2

• How many times does 1 go into 2? Also 2 times,

2 = 2 + 1 = 2×1 + 0 = 2×3⁰

So we found

857 = 1×3⁶ + 1×3⁴ + 1×3³ + 2×3² + 2×3⁰

which is the ternary expansion of <em>x</em>,

<em>x</em> = 1 011 202₃

6 0
2 years ago
A submarine sits at -300 meters in relation to sea level. Then it descends 115 meters. What is it’s new position in relation to
Anna71 [15]

Answer:

A. -415m

Step-by-step explanation:

-300 meters is the starting point.

Then, the submarine goes 115m further below the surface, which can be represented as -115.

Add -300 and -115 and you get -415m.

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4' 9''+ 7''<br> the sum pleaseee
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Answer:

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Step-by-step explanation:

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2 years ago
Please show work for both problems
kirill [66]

Answer:

3)  x = 15; 95 and 85      4)  x = 12; 98 for both angles

Step-by-step explanation:

2x + 65 + 3x + 40 = 180       Set the equations equal to 180

5x + 105 = 180                      Combine like terms

     - 105  - 105                      Subtract 105 from both sides

5x = 75                                  Divide both sides by 5

x = 15

Plug 15 into both equations

2(15) + 65 = 95

3(15) + 40 = 85

4)  5x + 38 = 9x - 10             Set the equations equal to each other

  - 5x          - 5x                    Subtract 5x from both sides

 38 = 4x - 10

+ 10       + 10                         Add 10 to both sides

48 = 4x                                  Divide both sides by 4

12 = x

Plug 12 into both equations

5(12) + 38 = 98

9(12) - 10 = 98

6 0
2 years ago
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