1. Quadrilateral ABCD is inscribed in circle O
A quadrilateral is a four sided figure, in this case ABCD is a cyclic quadrilateral such that all its vertices touches the circumference of the circle.
A cyclic quadrilateral is a four sided figure with all its vertices touching the circumference of a circle.
2. mBCD = 2 (m∠A) = Inscribed Angle Theorem
An inscribed angle is an angle with its vertex on the circle, formed by two intersecting chords.
Such that Inscribed angle = 1/2 Intercepted Arc
In this case the inscribed angle is m∠A and the intercepted arc is MBCD
Therefore; m∠A = 1/2 mBCD
4. The sum of arcs that make up a circle is 360
Therefore; mBCD + mDAB = 360°
The circles is made up of arc BCD and arc DAB, therefore the sum angle of the arcs is equivalent to 360°
5. 2(m∠A + 2(m∠C) = 360; this is substitution property
From step 4 we stated that mBCD +mDAB = 360
but from the inscribed angle theorem;
mBCD= 2 (m∠A) and mDAB = 2(m∠C)
Therefore; substituting in the equation in step 4 we get;
2(m∠A) + 2(m∠C) = 360
B. the middle half of the data set
Answer:
1.81 kilograms
Step-by-step explanation:
Answer:
(0,-3) will give the maximum value
Step-by-step explanation:
To know the vertex, we have to substitute the coordinates in the options
we have this as follows
a) (1.5,0)
T = 1.5-3(0) = -1.5
b) (3.5,4)
T = 3.5 - 1)4)
= 3.5 - 4 = -0.5
c) (0,-3)
we have
T = 0-3(-3) = 0 + 9 = 9
d) (0,4)
we have this as:
T = 0 - 3(4) = -12
0.000038 = 3.8e-5 = 3.8×10⁻⁵
