Answer:
the answer is A
Step-by-step explanation:
Answer:
13 < 3x+3 < 16
4, 5, 6
Step-by-step explanation:
First, we know that the numbers are consecutive, so they are one after another on the number line. If the smallest one is x, the next one is x+1 and the next is x+2. The sum of them is x+x+1+x+2, or 3x+3. The sum is more than 13 and less than 16 because the problem says between, not equal to or between. To solve, subtract 3 from all three sides of the inequality to get "10 < 3x < 13". Finally, divide all of the sides by 3 to get "3.33 < x < 4.33". The only whole number in between those is 4, so the smallest number of the sequence is 4. The following numbers are 5 (x+1, 4+1) and 6 (x+2, 4+2).
3(x-1)-2•(2x+1)=8(x-1)
3x-3-4x+2=8x-8
3x-3-4x+2-8x+8=0
-9x+7=0
-9x=-7
x= 7/9
Answer:
5/9
Step-by-step explanation:
altogether there are 9 pieces on the counter 5 of them are bananas so there would be a 5/9 chance of picking up a banana
To solve this, you have to figure out how they created the sequence, i.e., how did they get from 28 to 33 and then from 33 to 38 (etc.). If you subtract 28 from 33 the answer is 5, and the same is true for all the consecutive numbers in the sequence, so you have to add five to 43 to figure out the next term. You already have four terms, so we only need 4 more:
28, 33, 38, 43, 48, 53, 58, 63 63 is the 8th term.