F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21
Answer:
Part A: a coefficient is either 20 or 35, both work. A variable is c or w, again either work. The constant is 23.50.
Part B: He will have $503.50
Part C: The coefficient would change, because the amount per car changes, not the amount of cars.
Step-by-step explanation:
A coefficient goes in front of the variable (which is the letter, usually shown as x). The constant is a number with no variable attached.
We replace c with 20, and w with 12, giving us 20(3)+35(12)+23.50 for our equation. After multiplying, we come up with 60+420+23.50, which equals 503.50.
Answer:
DB = 24
Step-by-step explanation:
First, note that the diagonals of a rectangle are equal and bisect each other. In other words, DB = CA and CE = EA and DE = BE.
Also, AE + CE = CA
So, using this, we can write this equation:
AE = CE
x + 4 = 3x -12
Subtract 4 from both sides.
x = 3x -16
Subtract 3x from both sides.
-2x = -16
Divide both sides by -2
x = 8
Then, substitute this into AE + CE = CA
x + 4 + 3x - 12 =
8 + 4 + 24 - 12 = 24
Then, because CA = DB,
DB = 24
I hope this helps! Feel free to ask any questions! :)
Answer:
Step-by-step explanation:
<u>Given data:</u>
Base = b = 4 cm
Height = h = 4 cm
<u>Required:</u>
Area of triangle = A = ?
<u>Formula:</u>
A = bh / 2
<u>Solution:</u>
A = (4)(4) / 2
A = 16 / 2
A = 8 cm²
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
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