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mihalych1998 [28]
2 years ago
6

Please Help Me Asap I Need Units Too

Mathematics
1 answer:
Lina20 [59]2 years ago
3 0

Hello and Good Morning/Afternoon

<u>Let's take this problem step by step</u>:

<u>To find the rate of change is essentially like finding a line's slope</u>:

 ⇒ the <em>x-values</em> are the <em>number of sodas</em>

 ⇒ the<em> y-values </em>are the <em>total costs</em>

<em>               ⇒ choose</em> two sets of coordinates and find the slope

<u>Let's put that into action</u>

  • Choose any two points

        ⇒ (24, 18)

        ⇒ (28, 21)

  • Calculate Slope

        Rate_.of_.change = \frac{21-18}{28-24} =\frac{3}{4}

<u>Since the rate of change is total cost over number of sodas</u>

 ⇒ <em>unit is '</em>total cost/number of sodas'

<u>Answer: 3/4 total cost/number of sodas</u>

<u></u>

Hope that helps!

#LearnwithBrainly

<u><em /></u>

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77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

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= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

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= \cos^{3} x\sin^{2} x

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{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

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80. Left hand side  

= \sin^{4}x - \cos^{4}x

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{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

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