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Stells [14]
3 years ago
7

Can someone please help me out with this

Mathematics
1 answer:
ehidna [41]3 years ago
4 0
The answer is 43 degrees.

Explanation:

Because that corner of the quadrilateral is equivalent to 90 degrees, the other angle would need to equal 90 when added together with 43.

To find the answer, you simply subtract 47 from 90, and you have found the answer, which, in this case, is 43 degrees.

Hope this helped! Have a good day.
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Evaluate the expression when x=7 and y=-3. 5y2-x
DIA [1.3K]

Answer:

-37

Step-by-step explanation:

It would be greatly appreciated if you gave me brainlest

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2 years ago
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In what situation might you have to calculate the surface area of volume of a solid?
Digiron [165]
One application of volume is determining the density of an object. Assume the object is made of a pure element (eg: gold). If we know the volume (v) of the object, and we know the mass (m), then we can use the formula D = m/v to figure out the density D. Knowing the volume is also handy to determine if the object can fit into a larger space or not. Another application is figuring out how much water is needed to fill up the inner space of the 3D solid (assuming it's hollow on the inside).

The surface area is handy to figure out how much material is needed to cover the outer surface. This material can be paint, paper, metal sheets, or whatever you can think of really. A good example is wrapping a present and the assumption is that there is no overlap. 
8 0
3 years ago
Jade wants to solve -5.5 -(-3.5) and model it on a number line.
Liono4ka [1.6K]
- 5.5 + 3.5
the answer is -2

first you soustracte. -

- × - = +
5 0
3 years ago
Based on the information below, what are the values of x and y of the solution to the system of equations used to create the inf
Alborosie

Answer:

Option D) is correct

That is x=2 , y=-5

Step-by-step explanation:

Given that the |A|=\left| \begin{array}{cc}4&-6\\ 8&-2\end{array}\right|, \left|A_x\right|=\left|\begin{array}{cc}38&-6\\ 28&-2\end{array}\right|, \left|A_y\right|=\left|\begin{array}{cc}4&38\\ 8&26\end{array}\right|

To find their determinants

|A|=\left| \begin{array}{cc}4&-6\\ 8&-2\end{array}\right|

=-8+48

=40

Therefore |A|=40

|A_x|=\left|\begin{array}{cc}38&-6\\ 28&-2\end{array}\right|

=-76+156

=80

Therefore |A_x|=80

|A_y|=\left|\begin{array}{cc}4&38\\ 8&26\end{array}\right|

=104-304

=-200

Therefore |A_y|=-200

To find the values of x and y:

x=\frac{|A_x|}{|A|}\ \textrm{and}\ y=\frac{|A_y|}{|A|}

x=\frac{80}{40} and y=\frac{-200}{40}

x=2 and y=-5

Option D) is correct

That is x=2 , y=-5

7 0
3 years ago
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How do I graph this ? PleAse help
azamat

Answer:

the slope is 1 up and 7 left (mx part of the equation) and the 2 is where you start on the y axis. So you start at 2 on the vertical axis, and move up one and left 7, and put a point on where you land and continue.

Step-by-step explanation:

It should look something like this: hope this helps :)

4 0
2 years ago
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