We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
Answer:
what do you mean?
Step-by-step explanation:
Answer:
i believe no solution
Step-by-step explanation:
Answer:
If you're solving for F then F=1. If you're solving for x then there's no solution
