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2 years ago

True or false: The graph of y=3x2-3 opens up.

Mathematics

1 answer:

Nady [450]2 years ago

5 0

Answer: True: The graph of y=3x²-3 opens up

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: (0,−3)(0,-3)

Focus: (0,−35/12)

Axis of Symmetry: x=0

Directrix: y=−37/12

X={-2, -1, 0, 1, 2}

Y={9, 0, -3, 0, 9

Step-by-step explanation:

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If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calcul

Wittaler [7]

Answer:

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

3 failures every twenty weeks

This means that for 1 week, $\mu = \frac{3}{20} = 0.15$

Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607$

$P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898$

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

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