Answer:
45 ways
Step-by-step explanation:
We are given;
there are 3 different math courses, 3 different science courses, and 5 different history courses.
Thus;
Number ways to take math course = 3
The number of ways to take science course = 3
The number of ways to take history course = 5
Now, if a student must take one of each course, the different ways it can be done is;
possible ways = 3 x 3 x 5 = 45 ways.
Thus, number of different ways in which a student must take one of each subject is 45 ways.
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
assuming 
Then the column values for base five here are
5³ 5² 
We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x → 19 - 15 = 4
and 4 = 4 ×
Thus = 
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219
Answer:
The answer is £52.8
Step-by-step explanation:
The answer is C 16 I believe
